8/19/2026 at 10:03:07 AM
Thinking this approach out, could someone correct me if I have this wrong.So he gradually increases the energy transfer from the weight to the arm over the course of the drop. But that arm swinging around must have a lot of energy loss due to friction and air resistance.
This loss will rise exponentially with the speed increase right? So in a sense he is holding his energy budget in a very inefficient phase, with high losses.
Two things support this. A) he spent a lot of time trying to make the arm more arodynamic. B) The spool widening at the end, which is essentially changing back down gears, applying more torque, right at the end when you want speed.
An alternative would be to drop the weight, and let it fall unrestricted until it gets to it's highest speed (this would minimise friction and air resistance) and only at the end of its fall, transfer the energy into the arm.
In this case the arm would only need to rotate 180 degrees or whatever, and not waste energy rotating right?
And then, to take this a step further to make this work there would need to be some flexibility or elasticity in the system to take energy from the high speed falling weight to the arm.
And what you have ended up with is something that looks like.... A whip!
by roomey
8/19/2026 at 3:53:30 PM
He could have also used some kind of chemical reaction contained within a rigid tube to transfer the energy to a projectile, but I think he just really likes trebuchets in particular.by cjcole
8/19/2026 at 11:43:05 PM
Macgyver Gets Lazy https://xkcd.com/444/by Cycl0ps
8/19/2026 at 10:54:24 AM
Energy loss from air resistance typically is quadratic, not exponential, with regard to velocity. So it’s worth much less than you’re arguing. And the arm has to rotate from what I can understand, so the end rotational velocity - and hence, rotational energy - would be the same?by pletnes
8/20/2026 at 5:25:25 PM
Any idea how adding a flywheel to the system would change it? Could we store more energy in the arm?by chocrates
8/19/2026 at 4:28:39 PM
Isn't drag either linear (proportional to velocity) or quadratic (proportional to velocity squared) depending on the scenario? But yes quadratic for things at this scale?by getlawgdon
8/19/2026 at 5:49:40 PM
Drag is linear with velocity under Stokes' Law which assumes laminar flow and a very very low Reynolds number, and does not apply to ballistic projectiles flying through air.Aerodynamic drag on the kinds of things that are involved in trebuchets is always quadratic with velocity.
by stackghost
8/19/2026 at 10:20:32 AM
If I'm picturing what you're explaining correctly, I think this would be difficult. Suddenly accelerating the arm from zero to hundreds of mph would put immense stress on the arm, not to mention whatever you're planning on using to transfer that energy (you kinda hand waved that bit).I think your assessment is correct about the energy losses. I'm just not sure about the fix.
by fooqux
8/19/2026 at 10:35:46 AM
I think the fix is essentially a whip, that's what I meant by elasticity and flexibility.If you want to accelerate a weight quickly in a single swipe, (simplified) gradually reducing the mass along the length of the whip imparts more kenetic energy at the end (the whip crack).
So the arm would no longer be rigid, although you can see in the OPs video it isn't actually fully rigid.
by roomey
8/19/2026 at 2:36:41 PM
I strongly suggest you get into trebuchet building! It is a fascinating mixture of art + science. You can start with legos or a few popsicle sticks, paint sticks + screws, etc.To make things easier, start with an "integrated sling ballistic" (ie: a piece of thread between two lego pieces). Sling release is actually fairly complicated so chop it out!
The arm is generally a rigid lever, and the sling acts exactly as your "gradually reducing mass". In his design you can see the kindof bike gear shape at the axle and eventually coming like an "A" towards the tip (and reducing to "infinite thin-ness" via the string/sling).
After you've built one simple (small) trebuchet, test to failure! How much weight can you stack on it before a component breaks (bucket? arm? axle? sling? frame?). How heavy of an object can you throw before "everything starts messing up"?
My recommendation for ballistics is mini-marshmallow (desktop), regular marshmallow, mega-marshmallow, then switch to "hard" ballistics, eg: mini candy pumpkin (the connoisseurs choice), tennis ball, basket ball, etc.
Once you start throwing dense, solid objects (marbles, golf balls, baseballs) your risk of property damage and injury goes up fairly exponentially, so stick to marshmallows and tennis balls until you feel more comfortable.
Spend lots of time figuring out safe/reliable trigger mechanisms, WITH A SAFETY! For my tennis-ball treb, I did three eyebolts with a dumb screwdriver on a string, and a vise-grip (clamping) on the far side. Eventually, you're trying to safely "release" 100's of pounds that is being held in tension, and if you have a misfire (fail to release trigger) you're potentially approaching a "loaded" machine which is demonstrably "not working right". Lifting/loading 100's of pounds and then having an unlocked trigger (which _also_ may fail) is not safe for anyone.
by ramses0
8/19/2026 at 11:28:48 AM
Nothing above absolute zero is fully rigid.You're going to transfer the energy quickly, you'll just break any "arm" that's light enough to accelerate with the energy available.
You could maybe use an 'already broken' arm (rope, like a whip) but then it's not a trebuchet.
by pbhjpbhj
8/19/2026 at 11:25:46 AM
The arm (or whip) would still have to accelerate from 0 to ~2000+ rpm on half a revolution even though its flexible. So there would still be enormous accelerations even though the whip eventually partly smoothens out the peak acceleration. it would be more like a collision which in turns introduces higher stresses (and probably vibrations too) to the system. Both requiring you to increase the strength + rigidity of the system and hence also increase weight on the arm. Which in turns increases inertia and the "collision" effect.Not saying its impossible to create a successful system like that, in fact it sounds sort of a natural/organic design that potential could be closer to the optimal design, but it would be more difficult to accomplish and probably need more testing and design iterations. So I think OPs strategy is more simple and pragmatic in this case.
by lovlar
8/19/2026 at 6:49:36 PM
If you remove the arm, is it still a trebuchet? Even the current design is pushing definition of trebuchet. That said, a gravity powered supersonic whip-a-pult would be pretty awesome :)by b_t_s
8/19/2026 at 12:14:11 PM
One could test this manually with a whip, right? Attach the ball at the end and try to crack it.by gniv
8/19/2026 at 1:38:46 PM
You'd need to build a very large, very heavy whip, like a chain whip but those only work laying on the ground due to how heavy they are, because the mass at the very end of a whip gets going so fast /because/ it's extremely light compared to the rest of the whip. So scaling up the weight to even a few grams of projectile means the rest of the whip gets very heavy.by rtkwe
8/19/2026 at 5:23:39 PM
He talks about reducing the drag by improving the aerodynamics of various components and got a 17.8% increase in it's RPM with just a leading edge profile and wrapping it in mylar.The big issue in your proposed version is building an arm that is light enough to not absorb a lot of energy (it still needs to be rotating at the same speed as the progressive version in the video) but rigid enough to survive that sudden acceleration. My bet is you'd lose way more to the arm flexing and the added weight than you would the benefit of not dealing with aerodynamic losses.
by rtkwe
8/19/2026 at 3:32:11 PM
>And what you have ended up with is something that looks like.... A whip!Had a similar feeling come to me as I watched this video a few weeks ago. It made me really want to see someone make a whip-based trebuchet that uses a big spring like https://www.youtube.com/watch?v=PkQZU-CBwhk
by jotux
8/19/2026 at 3:42:04 PM
Whips work because they gradually get lighter and lighter along their length meaning the same energy as it propagates down the length results in higher and higher speeds. Strapping a projectile to the end throws all of that off unless you make the whip extremely heavy to compensate.by rtkwe
8/20/2026 at 4:33:00 PM
Not sure if you watched the video, but the chain they're using is extremely heavy. I would think the projectile would be on the order of one of the single chain links at the end of the small side.by jotux
8/21/2026 at 9:08:06 AM
A 3d printed ball like in the OPs video would only be less than 3grams I imagine.Either way, the weight of the whip is hardly important right, as you are just doing an energy transfer from the falling weight into the small ball, the lighter the whip the better, as long as it doesn't break. If the whip is heavier, it will soak up the energy budget in momentum
by roomey
8/20/2026 at 1:55:50 AM
So what you're saying is he should extend the drop height a bit to run a vacuum pump before engaging? Sounds like he's on the path to launch some satellites!by nomel
8/20/2026 at 2:24:11 AM
I thi k the G forces involved to accelerate the arm to supersonic speeds in one rotation would tear it apart.by polishdude20