4/21/2025 at 7:17:34 PM
> Prior to this new finding, all the black holes that have been identified have also had a companion star—they are discovered due to their impact on light emitted by their companion star. Without such a companion star, it would be very difficult to see a black hole.It seems like we think there's many more of these black holes, but we just can't see them
by OsrsNeedsf2P
4/21/2025 at 7:29:55 PM
Lone stars are actually the exception, so not radically more as you might think. But there are also binary black holes.by adastra22
4/21/2025 at 9:33:14 PM
This only covers stellar black holes. (Note that this black hole is believed to be a stellar black hole.) Those statistics could change quickly if you add to it a currently unknown number of primordial black holes that arose around the Big Bang.If those primordial black holes are mostly on their own, and are both numerous and small, they make a potential candidate for dark matter. They could also be potentially small enough to be evaporating in our current era. This has been suggested as a potential source of a very high energy neutrino that was found in February. See https://www.livescience.com/space/black-holes/evidence-for-s....
(Note that this is just a single observation. We are a very long way from being able to obtain strong experimental evidence for such speculative theories.)
by btilly
4/22/2025 at 3:31:46 AM
PBHs can't be too small, since they'd have evaporated by now, but if they're large enough to last several times longer than our current universe age then perhaps there could be lots and we not be able to see them.by cryptonector
4/22/2025 at 5:06:37 AM
My understanding is that they can't be _ultramicroscopic_, but they can be quite small. According to the Wikipedia:> A primordial black hole with an initial mass of around 10^12 kg would be completing its evaporation today
And according to this:
https://www.omnicalculator.com/physics/schwarzschild-radius
Mass: 10e12 kg → Schwarzschild radius of 1.5e-14 m which is smaller than a hydrogen atom (5.3e−11 m).
I wonder what would be the mass that'd keep a black hole in thermal equilibrium with the current background radiation...
(Edit. whoops, minus sign in a wrong place made the calculations haywire, fixed now.)
by GolDDranks
4/22/2025 at 8:25:47 AM
> I wonder what would be the mass that'd keep a black hole in thermal equilibrium with the current background radiation...About 4.5e22 kg, i.e. about 60% the mass of the Moon.
Note that over time, the CMB will cool and the equilibrium will be broken.
by antonvs
4/22/2025 at 5:19:53 AM
How does a black hole this small stay together. I assumed it was gravity pushing against the atomic forces.Is it a case of once you black, you never go back?
by casperc
4/22/2025 at 6:49:14 AM
Exactly. Once your object reaches the right radius it's done. It will 'evaporate' eventually. But it won't revert back.An interesting result is that you could, and this is very much beyond our engineering, manufacture black holes like this.
by clarionbell
4/22/2025 at 8:02:21 AM
Very cool. Is there a place I can read up on this?by casperc
4/22/2025 at 9:31:57 AM
https://en.wikipedia.org/wiki/Schwarzschild_radius The principle is simple. If something crosses it's Schwarzschild radius, it becomes a black hole. So if you had a very, very, obscenely large particle collider, you could start smashing heavy nuclei with enough force to get them within that radius. Then you would have to 'trap' the new micro-black hole in some way (possibly give it a charge) and 'feed' it more matter very, very quickly, before it evaporates.The evaporation is a bit trickier, also known as Hawking radiation. It has not been observed yet, but it's one of those cases when we are pretty sure something like it must be going on. Otherwise we have even bigger hole in our understanding of the universe.
Theory is more difficult, but the practical effect is relatively obvious. Once the 'surface temperature' of black hole reaches over that of microwave background, it will begin to evaporate. The process is slow at first, but non-linear. As black hole evaporates, it loses mass, but the temperature actually rises.
Eventually, the process should end with a gamma ray burst.
There is a lot of unknown in that.
Right now we are very, very far from doing any of this. We would need to achieve much higher strength of magnetic fields before we could even consider this. It may turn out, that it's easier just to "catch" an existing micro-black hole. If they exist that is.
by clarionbell
4/22/2025 at 2:47:32 PM
One way would be to make a "Kugelblitz". It works by concentrating a huge amount of energy in a very small space. Because of E=mc2, concentrating energy does the same thing as concentrating mass, and could create a black hole from which even the photons that created it can't escape, at least in theory.In practice, probably impossible, or at least well beyond our current technological capabilities.
by GuB-42
4/22/2025 at 5:25:25 AM
Nobody really knows for black holes of these sizes, because we don't have a theory of quantum gravity, but I think that answer according to general relativity would that the curvature is steep enough that escaping would require going faster than c, the universal speed limit, so it doesn't happen.by GolDDranks
4/22/2025 at 8:58:47 AM
Black holes are not held together by gravity. The geometry of spacetime inside the event horizon doesn't allow anything to move away from the singularity. All possible worldlines move closer to the singularity.by meindnoch
4/22/2025 at 1:18:52 PM
Except some radiation does leave, evidently. As far as I know, no one knows how or why. I hope we find out before I die. It’s such a fascinating, confusing aspect of black holesby steve_adams_86
4/22/2025 at 7:50:57 PM
>Except some radiation does leave, evidentlyWell, not evidently. Rather, theoretically. We don't have any evidence of this whatsoever, but quantum field theory predicts that it should happen. On the other hand, we don't have a unified theory of quantum physics and general relativity, so it may well turn out to be pure fantasy; an artifact of the intersection of two incomplete theories.
by meindnoch
4/22/2025 at 2:53:11 PM
The radiation you talk about, Hawking radiation, does not come from inside of the black hole. It is caused by the black hole but it is formed from beyond its event horizon.by Maxatar
4/22/2025 at 7:26:01 PM
Well, I’ve exposed myself. I don’t have a PhD in physics. In fact, I don’t know much about physics. Including the things I comment about on Hacker News (my bad).I’m not sure how I made it all these years thinking the radiation came from inside.
I see now that it’s hypothesized to be some crazy interplay of particles and antiparticles within vacuums in curved space time which leads to the black hole absorbing a lesser charged particle while the higher charged particle is emitted as radiation… Which incurs some sort of mass debt for the hole due to the rules of vacuums? I will have to read about it for a few years before it makes any sense. In the meantime I’ll avoid saying dumb things about it on the internet
by steve_adams_86
4/22/2025 at 8:33:31 PM
You didn't say anything dumb whatsoever. Your explanation of it comes from Hawking himself but it was more for illustrative purposes rather than a rigorous description of it.At any rate, even taking your description which certainly has merit, it is still not the case that the radiation comes from the inside of the black hole, from beyond the event horizon. Rather it's that just outside of the event horizon a virtual particle anti-particle pair is produced which has a combined energy of zero. One way their energies can add up to zero is for one to have positive energy and the other to have negative energy. The explanation then goes that the virtual particle with negative energy enters the black hole and the virtual particle with positive energy escapes, which results in the mass of the black hole decreasing. But both of these particles were formed outside of the black hole, not beyond the event horizon.
So yes the black hole loses mass, and yes for illustrative purposes one can think about a thought experiment involving the production of virtual particle anti-particles, but the key principle is that nothing escaped the black hole in the sense of coming from within the event horizon.
by Maxatar
4/22/2025 at 9:33:01 PM
Oh noes my friend.. Its not about negative energy, but background (void) temperature. The pair of particles (matter / anti-matter) spawn, cooling down the vacoom. Once they anihilate again, they change to energy (various photon emisions) increasing background temperature again. Thats why empty space is not at 0 kelvin. Every time such particle is absorbed by blackhole, it just increases it energy (and possibily mass). Not sure where that evaporation comes from ;)by Borg3
4/22/2025 at 9:47:54 PM
There is no singular "it". I am responding to someone else who came to understand Hawking radiation through a thought experiment that Hawking himself described for pedagogical purposes.A brief description of that thought experiment involving negative energy can be found here along with the appropriate citation coming from Hawking's "A Brief History of Time":
https://en.wikipedia.org/wiki/Negative_energy#Hawking_radiat...
>Virtual particles can exist for a short period. When a pair of such particles appears next to a black hole's event horizon, one of them may get drawn in. This rotates its Killing vector so that its energy becomes negative and the pair have no net energy. This allows them to become real and the positive particle escapes as Hawking radiation, while the negative-energy particle reduces the black hole's net energy. Thus, a black hole may slowly evaporate.
by Maxatar
4/22/2025 at 2:48:00 PM
Stephen Hawking had a pretty good idea as to how and why - https://en.wikipedia.org/wiki/Hawking_radiationThis is not to be confused with the infrared light that’s relatively easy to detect, which isn’t leaving the black hole but is just light emitted from matter heating up due to tidal forces near the black hole.
I don’t think humanity is ever really going to know what a black hole actually is, simply because they’re too far away and the energy levels required for experiments are many many orders of magnitude beyond what we can generate on Earth. But I do expect if we could get up close and study one, we’d simply discover a lot of fascinating new physics over top of some kind of matter not that far off from neutron stars.
A lot of people don’t really get past the pop science articles about “singularities” to realize that those are just failures of our theories. We don’t know how anything behaves when gravity is strong enough to affect the quantum level, because QM has some kind of silly techniques for avoiding it under normal circumstances (called renormalization) that no longer work.
At extremely high energy levels, my guess as a guy on the internet is that the universe looks less like magical portals to Matthew McConaughey’s bookshelf, but more like regular boring space crap that destroys our notions of stuff like time, matter, energy, causality etc. And in fairness, neutron stars already kind of do this, but nobody cares for some reason.
by lqstuart
4/22/2025 at 3:46:33 PM
[flagged]by Projectiboga
4/21/2025 at 10:54:33 PM
I thought there were too many constraints to make PBHs a significant contributor?by MichaelZuo
4/22/2025 at 2:18:30 AM
My understanding is that we can rule out having too many really small ones (we'd see them evaporating) and we can rule out too many stellar sized ones (gravitational lensing), but we haven't ruled out black holes in size ranges of a moon to a planet.But I don't track this field. So there could well be research that I don't know about which puts bigger constraints on it.
by btilly
4/22/2025 at 3:42:41 AM
Is black hole evaporation experimentally confirmed in any way?by adrianN
4/22/2025 at 3:48:48 AM
The only thing that I've seen cited as potential evidence either way is that one neutrino, with an energy too high for other mechanisms that we have thought of.But it is just a single neutrino. And it may be produced by a mechanism we haven't yet thought of.
The black holes that we know about are large. Large black holes are supposed to emit so little radiation that we'd never be able to detect it.
by btilly
4/22/2025 at 6:28:38 AM
If the hawking temperature is higher than the CMB, would there be any net evaporation at all?A BH needs to be truly tiny for it to be hotter than the CMB
by ithkuil
4/22/2025 at 8:45:39 AM
Large black holes do have significant accretion disks that do impact their visibility and can and will spew forth vast amounts of radiation. Anything caught in their event horizon gets pulled in and is never seen again. Anything near it bumps into other things in orbit around it, which lights it up like a candle.Note that there is also a 'weight class' of black holes that are significantly large that their event horizon would be visible to the naked eye, but which don't have an accretion disk. We currently don't know enough to make scientific estimates on how many of each weight class exists.
by once_inc
4/22/2025 at 5:02:25 PM
That is light coming from the accretion disk, and things falling it. The light does not come from the black hole itself.by btilly
4/22/2025 at 5:58:13 PM
Yes and no. The mechanism for evaporation is a straightforward implication of matter/antimatter pair production in the vicinity of the event horizon. This general phenomenon (minus the event horizon) is observed every day in particle accelerators. But the signal would be too small to detect from any black hole we do know about.by adastra22
4/22/2025 at 3:18:21 AM
That depends on how you're counting.About 2/3 of star systems have only one star.
About 2/3 of stars exist in a system with multiple stars.
However, the higher the mass, the more likely it is to be in a multiple-star system. For stars with a mass high enough to form a black hole ... hm, Wikipedia says "at least 80%" but makes it unclear which statistic is being measured.
by o11c
4/22/2025 at 3:30:21 AM
> But there are also binary black holes.A binary black hole system will keep any other companions quite far from the binary, and perhaps not even allow companions at any distance. What is the density of lone black holes and black hole binaries that we could have in -say- our galaxy before we would notice them frequently in the same way as in TFA? Well, presumably LIGO would sense them, or could if they knew what to look for.
by cryptonector
4/22/2025 at 3:55:53 AM
LIGO does sense them, or at least the infrequent merges.by adastra22
4/22/2025 at 5:01:48 AM
Yes, the mergers. I'm just wondering about binaries that are millions of years from merging.by cryptonector
4/22/2025 at 3:33:20 PM
Fun to realize there's barely any way for us to detect if there's one heading for us right this very moment.by qoez
4/22/2025 at 8:16:49 PM
Thankfully the speed of light is slow enough to where that's not a huge concern... that is, unless the Nemesis hypotheses is actually a black hole and not a brown dwarf or planet.by scoofy
4/21/2025 at 8:38:00 PM
A type-1a supernova peer would produce this effect, leaving only the black hole (or the oversize star that would become it). I don't know any other types where the star is completely destroyed.by chasil